Iridium Ir
Iridium is the 77 element in periodic table situated in 6 period.| Symbol | Ir |
| Number | 77 |
| Atomic weight | 192.2170000 |
| Latin name | Iridium |
| English name | Iridium |
Electronic configuration of of Iridium
Ir: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d7
Short notation:
Ir: [Xe]6s2 4f14 5d7
The order of filling the shells with electrons of Iridium (Ir): 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p.
On the sub level ‘s’ there might be 2 electrons at most, on ‘p’ - up to 6, on ‘d’ - up to 10 and up to 14 on ‘f’
Iridium has 77 electrons, let's fill electronic layers in described order:
2 electrons on 1s-sub level
2 electrons on 2s-sub level
6 electrons on 2p-sub level
2 electrons on 3s-sub level
6 electrons on 3p-sub level
2 electrons on 4s-sub level
10 electrons on 3d-sub level
6 electrons on 4p-sub level
2 electrons on 5s-sub level
10 electrons on 4d-sub level
6 electrons on 5p-sub level
2 electrons on 6s-sub level
14 electrons on 4f-sub level
7 electrons on 5d-sub level
Oxidation state of Iridium
Atoms of Iridium in compounds have an oxidation state of 6, 5, 4, 3, 2, 1, 0, -1.
The oxidation state is the conditional charge of an atom in a compound: the bond in a molecule between atoms is based on the sharing of electrons, thus, if the atom’s charge virtually increases, then the oxidation state is negative (electrons carry a negative charge), if the charge decreases, then the oxidation state is positive.
Ions of Iridium
Valence of Ir
Atoms of Iridium in compounds have valence VI, V, IV, III, II, I.
Valence of Iridium is an ability of an atom Ir to build chemical bounds. The valence is based on electronic configuration of atom: electrons participated in chemical bounds are known as valence electrons. In general the valence is:
The number of possible chemical bounds with other atoms
The valence has no sign.
Quantum numbers Ir
Quantum numbers are defined by the last electron in configuration, for an atom Ir these numbers are N = 5, L = 2, Ml = -1, Ms = -½
Filling an electronic configuration (gif):
Result:
Ionization energy
The closer the electron is to the center of the atom, the more energy is needed to tear it off. The energy spent on removing an electron from an atom is called ionization energy and is designated Eo. Unless otherwise stated, the ionization energy is the energy of removal of the first electron, and there are also ionization energies for each subsequent electron.
Ionization energy of Ir:
Eo = 880 kJ/mol
See all elements of the periodic table
Where is Ir in the periodic table?
