Ion Na^- (Minus one)

Symbol	Na-
Number	11
Atomic weight	22.9897693
Latin name	Natrium
English name	Sodium

How to build an electronic configuration by yourself? See link

Electronic configuration of of Sodium

Na: 1s² 2s² 2p⁶ 3s¹ → Na^-:1s²2s²2p⁶3s²

Same electronic configuration has an ion of Sodium -1 and Mg, Al⁺¹, Si⁺², P⁺³, S⁺⁴, Cl⁺⁵

The order of filling the shells with electrons of Sodium (Na^-): 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p.

On the sub level ‘s’ there might be 2 electrons at most, on ‘p’ - up to 6, on ‘d’ - up to 10 and up to 14 on ‘f’

Sodium has 11 electrons, let's fill electronic layers in described order:

2 electrons on 1s-sub level

2 electrons on 2s-sub level

6 electrons on 2p-sub level

2 electrons on 3s-sub level

Oxidation state of Sodium

Atoms of Sodium in compounds have an oxidation state of 1, -1.

The oxidation state is the conditional charge of an atom in a compound: the bond in a molecule between atoms is based on the sharing of electrons, thus, if the atom’s charge virtually increases, then the oxidation state is negative (electrons carry a negative charge), if the charge decreases, then the oxidation state is positive.

Oxidation state of an ion Na^- = -1

Ions of Sodium

Valence of Na^-

Atoms of Sodium in compounds have valence I.

Valence of Sodium is an ability of an atom Na to build chemical bounds. The valence is based on electronic configuration of atom: electrons participated in chemical bounds are known as valence electrons. In general the valence is:

The number of possible chemical bounds with other atoms

The valence has no sign.

Quantum numbers Na ^1-

Quantum numbers are defined by the last electron in configuration, for an ion Na these numbers are N = 3, L = 0, M_l = 1, M_s = -½

Filling an electronic configuration (gif):



Result: