Ion Sr2+
Symbol | Sr2+ |
Number | 38 |
Atomic weight | 87.6200000 |
Latin name | Strontium |
English name | Strontium |
Electronic configuration of of Strontium
Sr: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 → Sr2+:1s22s22p63s23p64s23d104p65s0
Same electronic configuration has an ion of Strontium +2 and As-3, Se-2, Br-1, Kr, Rb+1, Y+3, Zr+4, Tc+7
The order of filling the shells with electrons of Strontium (Sr2+): 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p.
On the sub level ‘s’ there might be 2 electrons at most, on ‘p’ - up to 6, on ‘d’ - up to 10 and up to 14 on ‘f’
Strontium has 38 electrons, let's fill electronic layers in described order:
2 electrons on 1s-sub level
2 electrons on 2s-sub level
6 electrons on 2p-sub level
2 electrons on 3s-sub level
6 electrons on 3p-sub level
2 electrons on 4s-sub level
10 electrons on 3d-sub level
6 electrons on 4p-sub level
Oxidation state of Strontium
Atoms of Strontium in compounds have an oxidation state of 2.
The oxidation state is the conditional charge of an atom in a compound: the bond in a molecule between atoms is based on the sharing of electrons, thus, if the atom’s charge virtually increases, then the oxidation state is negative (electrons carry a negative charge), if the charge decreases, then the oxidation state is positive.
Oxidation state of an ion Sr2+ = 2
Ions of Strontium
Valence of Sr2+
Atoms of Strontium in compounds have valence II.
Valence of Strontium is an ability of an atom Sr to build chemical bounds. The valence is based on electronic configuration of atom: electrons participated in chemical bounds are known as valence electrons. In general the valence is:
The number of possible chemical bounds with other atoms
The valence has no sign.
Quantum numbers Sr 2+
Quantum numbers are defined by the last electron in configuration, for an ion Sr these numbers are N = 4, L = 1, Ml = 1, Ms = -½
Filling an electronic configuration (gif):Result:
See all elements of the periodic table
Where is Sr in the periodic table?