Ion V2+
Symbol | V2+ |
Number | 23 |
Atomic weight | 50.9415000 |
Latin name | Vanadium |
English name | Vanadium |
Electronic configuration of of Vanadium
V: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 → V2+:1s22s22p63s23p64s23d1
Same electronic configuration has an ion of Vanadium +2 and Sc, Mn+4, Fe+5
The order of filling the shells with electrons of Vanadium (V2+): 1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p → 5s → 4d → 5p → 6s → 4f → 5d → 6p → 7s → 5f → 6d → 7p.
On the sub level ‘s’ there might be 2 electrons at most, on ‘p’ - up to 6, on ‘d’ - up to 10 and up to 14 on ‘f’
Vanadium has 23 electrons, let's fill electronic layers in described order:
2 electrons on 1s-sub level
2 electrons on 2s-sub level
6 electrons on 2p-sub level
2 electrons on 3s-sub level
6 electrons on 3p-sub level
2 electrons on 4s-sub level
1 electron on 3d-sub level
Oxidation state of Vanadium
Atoms of Vanadium in compounds have an oxidation state of 5, 4, 3, 2, 1, 0, -1, -2.
The oxidation state is the conditional charge of an atom in a compound: the bond in a molecule between atoms is based on the sharing of electrons, thus, if the atom’s charge virtually increases, then the oxidation state is negative (electrons carry a negative charge), if the charge decreases, then the oxidation state is positive.
Oxidation state of an ion V2+ = 2
Ions of Vanadium
Valence of V2+
Atoms of Vanadium in compounds have valence V, IV, III, II, I.
Valence of Vanadium is an ability of an atom V to build chemical bounds. The valence is based on electronic configuration of atom: electrons participated in chemical bounds are known as valence electrons. In general the valence is:
The number of possible chemical bounds with other atoms
The valence has no sign.
Quantum numbers V 2+
Quantum numbers are defined by the last electron in configuration, for an ion V these numbers are N = 3, L = 2, Ml = -2, Ms = +½
Filling an electronic configuration (gif):Result:
See all elements of the periodic table
Where is V in the periodic table?